Utilizator:Mister rf/teste

$E$ $m$ $mf(t)$ $E_{m}$

$(2\pi f_{p}t)$ $e(t)$ ${\text{ω}}_{p}$

$e(t)=E_{m}(t)\cos a_{p}(t)$ ${\text{ω}}$

$e(t)=E_{m}(t)\cos {\text{ω}}_{p}(t)$

$E_{m}(t)=E[1+mf(t)]$

pentru $m=0$

$e(t)=E\cos {\text{ω}}_{p}(t)$ oscilatia purtatoare

$m$ grad de modulatie

$f(t)$ semnalul modulator normat cu

${\overline {f(t)}}=0$

$\left|f(t)\right|_{\text{max}}=1$

$f(t)=\cos {\text{ω}}t$

$e(t)=E_{m}(t)\cos {\text{ω}}_{p}(t)=E(1+m\cos {\text{ω}}(t))\cos {\text{ω}}_{p}(t)=E\cos {\text{ω}}t+mE\cos {\text{ω}}(t)\cos {\text{ω}}_{p}(t)=E\cos {\text{ω}}t+{\frac {mE}{2}}\cos({\text{ω}}_{p}+{\text{ω}})(t)+{\frac {mE}{2}}\cos({\text{ω}}_{p}-{\text{ω}})(t)$

${\frac {2{\text{ω}}_{M}}{2\pi }}={\frac {{\text{ω}}_{M}}{\pi }}=$ sau $2f_{M}$ unde $f_{M}={\frac {{\text{ω}}_{M}}{2\pi }}$